When a short-form "if" is directly followed by an "end", it causes an error:

function test(x)
 if (x==1) print "boo"
end

test(1)

Inserting a newline before the "end" fixes it:

function test(x)
 if (x==1) print "boo"

end

test(1)

v0.1.0 on Windows

Fixed for the next update (0.1.1)

An alternative workaround in the meantime is to put indentation before the if:

function test(x)
  if (x==1) print "boo"
end
test(1)

is also ok.

Apologies anyone who got stumped by this bug and the cryptic <eof> error message. So confusing!

Actually, I did write it this way (indented), but it was somehow trimmed away upon pasting the code.

I just tested it again, and indenting doesn't change the behavior for me; only the newline does.

Another interesting thing about the short-if is that a space is required between the ")" and expression,

if(w==nil) w=1 -- OK
if(w==nil)w=1 -- Error